Αλλαγή κύκλου με Cyclacur

Question

&Kappa;&alpha;&lambda;&eta;&sigma;&pi;έ&rho;&alpha;. Ύ&sigma;&tau;&epsilon;&rho;&alpha; &alpha;&pi;ό &epsilon;&pi;ί&sigma;&kappa;&epsilon;&psi;&eta; &mu;&omicron;&upsilon; &sigma;&tau;&omicron; &gamma;&upsilon;&nu;&alpha;&iota;&kappa;&omicron;&lambda;ό&gamma;&omicron; &alpha;&pi;&omicron;&phi;&alpha;&sigma;ί&sigma;&alpha;&mu;&epsilon; &nu;&alpha; &kappa;ά&nu;&omega; &theta;&epsilon;&rho;&alpha;&pi;&epsilon;ί&alpha; &lambda;ί&gamma;&omega;&nu; &eta;&mu;&epsilon;&rho;ώ&nu; &mu;&epsilon; &tau;&omicron; &phi;ά&rho;&mu;&alpha;&kappa;&omicron; Cyclacur ώ&sigma;&tau;&epsilon; &nu;&alpha; &mu;&pi;&omicron;&rho;έ&sigma;&omega; &nu;&alpha; &alpha;&lambda;&lambda;ά&xi;&omega; &lambda;&iota;&gamma;ά&kappa;&iota; &tau;&iota;&sigmaf; &eta;&mu;έ&rho;&epsilon;&sigmaf; &tau;&omicron;&upsilon; &kappa;ύ&kappa;&lambda;&omicron;&upsilon; &kappa;&alpha;&iota; &nu;&alpha; &mu;&pi;&omicron;&rho;έ&sigma;&omega; &nu;&alpha; &kappa;ά&nu;&omega; &tau;&alpha; &mu;&pi;ά&nu;&iota;&alpha; &mu;&omicron;&upsilon; . &Mu;&omicron;&upsilon; έ&delta;&omega;&sigma;&epsilon; &omicron;&delta;&eta;&gamma;ί&epsilon;&sigmaf; &lambda;ή&psi;&eta;&sigmaf; &mu;ό&nu;&omicron; &tau;&omicron;&upsilon; &kappa;&alpha;&phi;έ &delta;&iota;&sigma;&kappa;ί&omicron;&upsilon; &pi;&omicron;&upsilon; &pi;&epsilon;&rho;&iota;έ&chi;&epsilon;&tau;&alpha;&iota; &sigma;&tau;&omicron; &kappa;&omicron;&upsilon;&tau;ί 7 &eta;&mu;έ&rho;&epsilon;&sigmaf; (1 &delta;&iota;&sigma;&kappa;ί&omicron; &tau;&eta;&nu; &eta;&mu;έ&rho;&alpha;) &kappa;&alpha;&iota; &mu;&omicron;&upsilon; &epsilon;ί&pi;&epsilon; &pi;&omega;&sigmaf; 3 &mu;&epsilon; 4 &mu;έ&rho;&epsilon;&sigmaf; &mu;&epsilon;&tau;ά &theta;&alpha; έ&rho;&theta;&epsilon;&iota; &kappa;&alpha;&nu;&omicron;&nu;&iota;&kappa;ά &eta; &pi;&epsilon;&rho;ί&omicron;&delta;&omicron;&sigmaf;. &Epsilon;ί&mu;&alpha;&iota; &sigma;&tau;&eta;&nu; 4 &eta;&mu;έ&rho;&alpha; &kappa;&alpha;&iota; &delta;&epsilon;&nu; έ&chi;&omega; &delta;&epsilon;&iota; &kappa;ά&tau;&iota;.