Αίμα απο την θηλή

Question

&kappa;&alpha;&lambda;&eta;&sigma;&pi;έ&rho;&alpha;.&epsilon;&delta;&omega; &kappa;&alpha;&iota; 4 &mu;&epsilon;&rho;&epsilon;&sigmaf; &pi;&epsilon;&rho;ί&pi;&omicron;&upsilon; &epsilon;&nu;&iota;&omega;&theta;&alpha; &tau;&eta;&nu; &theta;&eta;&lambda;ή &alpha;&pi;&omicron; &tau;&omicron; &delta;&epsilon;&xi;ί &sigma;&tau;&eta;&theta;&omicron;&sigmaf; &nu;&alpha; &epsilon;&iota;&nu;&alpha;&iota; &epsilon;&rho;&epsilon;&theta;&iota;&sigma;&mu;έ&nu;&eta; &kappa;&alpha;&iota; &nu;&alpha; &pi;&omicron;&nu;&alpha;&epsilon;&iota; &lambda;&iota;&gamma;&omicron; &kappa;&alpha;&iota; &sigma;&eta;&mu;&epsilon;&rho;&alpha; &pi;&alpha;&rho;&alpha;&tau;&eta;&rho;&eta;&sigma;&alpha; &omicron;&tau;&iota; έ&beta;&gamma;&alpha;&lambda;&epsilon; &lambda;&iota;&gamma;&omicron; &alpha;ί&mu;&alpha;.&sigma;&epsilon; &tau;&iota; &omicron;&phi;&epsilon;ί&lambda;&epsilon;&tau;&alpha;&iota; &alpha;&upsilon;&tau;&omicron;;&nu;&alpha; &pi;&rho;&omicron;&sigma;&theta;&epsilon;&sigma;&omega; &omicron;&tau;&iota; &delta;&epsilon;&nu; &theta;&eta;&lambda;&alpha;&zeta;&omega; &omicron;&upsilon;&tau;&epsilon; &epsilon;&iota;&mu;&alpha;&iota; &epsilon;&gamma;&kappa;&upsilon;&omicron;&sigmaf;.&epsilon;&upsilon;&chi;&alpha;&rho;&iota;&sigma;&tau;&omega;