ΣΥΝΕΧΕΙΑ ΑΠΟ ΠΡΟΗΓΟΥΜΕΝΗ ΕΡΩΤΗΣΗ

Question

&Alpha;&Gamma;&Alpha;&Pi;&Eta;&Tau;&Epsilon; &Gamma;&Iota;&Alpha;&Tau;&Rho;&Epsilon; &Epsilon;&Gamma;&Omega; &Tau;&Omega;&Rho;&Alpha; &Pi;&Omicron;&Tau;&Epsilon; &Nu;&Alpha; &Pi;&Epsilon;&Rho;&Iota;&Mu;&Epsilon;&Nu;&Omega; &Tau;&Nu; &Epsilon;&Pi;&Omicron;&Mu;&Epsilon;&Nu;&Eta; &Mu; &Pi;&Epsilon;&Rho;&Iota;&Omicron;&Delta;&Omicron;?????&Nu;&Alpha; ,&Mu;&Epsilon;&Tau;&Rho;&Alpha;&Omega; &Alpha;&Pi; &Tau;&Eta;&Nu; &Alpha;&Rho;&Chi;&Eta; &Tau;&Eta;&Sigma; &Kappa;&Alpha;&Nu;&Omicron;&Nu;&Iota;&Kappa;&Eta;&Sigma; &Eta; &Alpha;&Pi;&Omicron; &Alpha;&Upsilon;&Tau;&Eta; &Mu;&Epsilon; &Tau;&Alpha; &Kappa;&Alpha;&Phi;&Epsilon; &Upsilon;&Gamma;&Rho;&Alpha;?????&Mu;&Epsilon;&Chi;&Rho;&Iota; &Kappa; &Sigma;&Eta;&Mu;&Epsilon;&Rho;&Alpha; &Kappa; &Gamma;&Iota;&Alpha; &Tau;&Rho;&Iota;&Tau;&Eta; &Mu;&Epsilon;&Rho;&Alpha; &Sigma;&Upsilon;&Nu;&Epsilon;&Chi;&Iota;&Zeta;&Omicron;&Nu;&Tau;&Alpha;&Iota;,..............